Предмет: Физика, автор: LenaVadim1999

помогите пожалуйста определить полное ускорение на ободе колеса r=0,6м,при t=3с,если w=11 рад/с,заранее спасибо

Ответы

Автор ответа: Аноним
0
Дано:
R = 0,6 м
t = 3 c
ω = 11 рад/с
___________
a - ?

Уравнение вращательного движения:
φ(t)=φ +ω₀·t+ε·t²/2

Угловая скорость - первая производная от φ(t):
ω(t) = ω₀ + ε·t
Считая ω₀=0, имеем:
11=ε·3
ε=11/3
Тангенциальное ускорение:
aτ=ε·R=11*0,6/3=2,2 м/с²

Нормальное ускорение:
an=ω²·R = 11²·0,6 ≈ 72 м/с²

Полное ускорение:
a = √ (an²+aτ²) = √(72²+2,2²) ≈  73 м/с²





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