Question

log π (x^2+2x+3)= log π 6

Answer 1

$log_{pi} (x^2+2x+3)=log_{pi} 6$
$x^2+2x+3=6$
$x^2+2x+3-6=0$
$x^2+2x-3=0$
$(x+3)(x-1)=0$
$x+3=0;x_1=-3$
$x-1=0;x_2=1$
ответ: -3; 1