Question

Помогиите найти производную y=(1-6x^2)/(2+4x)

Answer 1

y=(1-6x^2)/(2+4x)

y' =((1-6x^2)'(2+4x)-(2+4x)'(1-6x^2)) / (2+4x)^2

y' = (-4(6x^2+6x+1)) / (2+4x)

Answer 2

$y'=frac{(1-6x^2)'*(2+4x)-(1-6x^2)*(2+4x)'}{(2+4x)^2}=\=frac{-12x*(2+4x)-(1-6x^2)*4)}{(2+4x)^2}=\=frac{-24x-48x^2-4+24x^2}{(2+4x)^2}=frac{-24x^2-24x-4}{(2+4x)^2}$