Question

A-(3;-4),b-(2;6),c-(-2;0),найти P-?

Answer 1

Решение
A-(3;-4),b-(2;6),c-(-2;0)
AB = √[(2-3)² + (6 + 4)²] = √(1 + 100) = √101
AC = √[(-2 - 3)² + (0 + 4)²] = √[(-5)² + 4²] = √(25 + 16) = √41
BC = √[(- 2 - 2)² + (0-6)²] = √[(-4)² + (-6)²] = √(16 + 36) = √42
P = AB + AC + BC = √101 + √41 + √42