Question

x²+y=3
y-x+3=0
решите систему

Answer 1

Х^2 + y = 3
y - x + 3 = 0
••••••••••••••
y = 3 - x^2
y = x - 3
••••••••••••••
3 - x^2 = x - 3
X^2 - 3 + x - 3 = 0
X^2 + x - 6 = 0
D = 1 + 24 = 25 = 5^2
X1 = ( - 1 + 5 ) : 2 = 2
X2 = ( - 1 - 5 ) : 2 = - 3
y = x - 3
y1 = 2 - 3 = - 1
y2 = - 3 - 3 = - 6
Ответ ( 2 ; - 1 ) ; ( - 3 ; - 6 )

Answer 2

огромное спасибо! :)