Question

Найти производную функции.
1. cosx-tgx
2. 6x^4-9e^x
3. (1/3x^3)+1/2lnx
4. (x^3+1)cos2x

Answer 1

(сosx-tgx)`=-sinx-1/cos²x
(6x^4-9e^x)`=24x³-9e^x
[(1/3*x³)+1/2lnx]`=x²+1/(2x)
[(x³+1)cosx]`=(x³+1)`cosx+(x³+1)(cosx)`=3x²cosx-(x³+1)sinx