Question

log1/3(x^2-10x+10)=0 помогите плиз

Answer 1

Log(1/3)[$x^{2}$-10x+10]=Log(1/3)[1]
$x^{2}$-10x+10=1
$x^{2}$-10x+9=0
D=(-10)²-4×9=64
x₁=$frac{10+8}{2}$=9
x₂=$frac{10-8}{2}$=1