Предмет: Математика, автор: guldanakaskat

(x+3)(x+1)(x-4)^2 (x-5)<0
решите уравнение

Ответы

Автор ответа: dustInEyes

найдем нули функции
(х+3)(х+1)(х-4)²(х-5)<0

х1=-3
х2=-1
х3=4
x4=5

-3 -1 4 5
-------|-------|------|-------|-------
------- ++++ ----- ------- ++++

решение х∈(-∞; -3) ∪ (-1 ; 4) ∪ (4; 5)

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(x+3)(x+1)(x-4)^2 (x-5)<0 решите уравнение

Ответы

(x+3)(x+1)(x-4)^2 (x-5)<0
решите уравнение