Question

1)СosA=1/3
SinA=?

2)CosA=24/25
TgA-?

Answer 1

$cos a = frac13\ sin a = 1 - cos^2a=1-frac19=frac89\ \ cos a=frac{24}{25}\ tan a = frac{sin a}{cos a}=frac{1- cos ^2 a}{cos^2a}=frac{1-frac{576}{625}}{frac{576}{625}}=frac{49}{576}$