Question

2^x^2 > (1/2) ^2x-3 помогите

Answer 1

2^x²=2^(3-2x)
x²=3-2x
x²+2x-3=0
Д=4+12=16
x1=(-2+4)/2
x1=1;
x2=(-2-4)/2
x2=-3