Question

решить систему {y^2-2x^2=8 {x+y=6

Answer 1

Х + y = 6
y = 6 - x
y^2 = ( 6 - x )^2 = 36 - 12x + x^2
y^2 - 2x^2 = 8
y^2 = 2x^2 + 8
2x^2 + 8 = 36 - 12x + x^2
X^2 + 12x - 28 = 0
D = 144 + 112 = 256 = 16^2
X1 = ( - 12 + 16 ) : 2 = 2
X2 = ( - 12 - 16 ) : 2 = - 14
y = 6 - x
y1 = 6 - 2 = 4
y2 = 6 + 14 = 20
Ответ ( 2 ; 4 ) ; ( - 14 ; 20 )