Question

помогите sin2x=cos^2x

Answer 1

$sin2x=cos^2x\2sin xcos x-cos^2x=0\cos x(2sin x-cos x)=0\cos x=0Rightarrow x=fracpi2+pi n\\2sin x-cos x=0\2sin x=cos x\2tgx=1\tgx=frac12\x=arctgfrac12+pi n,;ninmathbb{Z}$