Question

(m-2)/(m^2-m-2)-m/(m^2-2m+1)

Answer 1

$frac{m-2}{(m+1)(m-2)}-frac{m}{(m-1)^2}=frac{1}{m+1}-frac{m}{(m-1)^2}=$ 

$=<var>frac{(m-1)^2-m(m+1)}{(m+1)(m-1)^2}=frac{m^2-2m+1-m^2-m}{(m+1)(m-1)^2}=</var>$ 

$=frac{1-3m}{(m+1)(m-1)^2}$