Question

упростить:$<var>\frac{2xy}{(2x+y)^2}}*\frac{4x^2-y^2}{-y}</var>$

 

Answer 1

$<var>\frac{2xy}{(2x+y)^2}}*\frac{4x^2-y^2}{-y}=-\frac{2x}{(2x+y)^2}}*\frac{(2x-y)(2x+y)}{1}=-\frac{2x}{2x+y}}*\frac{2x-y}{1}=\\\ =-\frac{4x^2-2xy}{2x+y} </var>$