Question

-х^{2}+4х-3=0

2 x^{2} +4х=0

-2 x^{2} +4х+6=0

Answer 1

3)-x²+4x-3=0
2x²+4x=0
-2x²+4x+6=0
-2(x²-2x-3)=0
-2(-x²+x-3x-3)=0
-2(x(x+1)-3(x+1)=0
-2(x-3)(x+1)=0
(x-3)(x+1)=0
x-3=0
x+1=0
x=3
x=-1
x1=3;x2=-1