Предмет: Физика, автор: чупик1

водоизмещение атомного ледокола,,Арктика,,234 600кН.Каков объём его подводной части?

Ответы

Автор ответа: Денис161

0

тк тело плавает на поверхности сила архимеда равна mg → m=rV

Fa=mg→m=600кН/10=60000кг=60тонн а как выразить объем если нам не дана плотность материала из которого он изготовлен

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