Question

помогите,плес.заранее спасибо <3

Answer 1

[(x³-2x²)/(3x+3)]:[(x²-4)/(3x²+6x+3)]=
=[x²·(x-2)/3·(x+1)]:[(x-2)·(x+2)/3·(x+1)²]=
=x²·(x-2)·3(x+1)²/3·(x+1)(x-2)(x+2)=x²(x+1)/(x+2)