Question

помогите пожалуста, срочно решите!! 

-√2  sin(-5π/2+x)*sinx=cosx  

[9π/2,9п]

Answer 1

-√2  sin(-5π/2+x)*sinx=cosx

√2  sin(5π/2-x)*sinx=cosx

√2  sin(π/2-x)*sinx=cosx

√2  cosx*sinx=cosx

cosx(√2sinx-1)=0

x=π/2+π*n

x=π/4+2π*m

x=3π/4+2π*m

 

x=4,5π;5,5π;6,5π;7,5π;8,5π;π/4+6π, π/4+8π, 3π/4+6π, 3π/4+8π