Question

Решите пожалуйста 16.17 б-г

Answer 1

(log6(12) +log6(4))/(log6(3)+log6(16))=(log6(12*4))/(log6(3*16))=log6(48)/log6(48)=1
(log0,3(16))/(log0,3(15)-log0.3(30))=log0.3(16)/log0.3(1/2)=log1/2(16)=-4