Предмет: Геометрия, автор: Лиза991652638392

к окружости с центром в точке О проведены касательная аб и секущая ао. найдите радиус окружности, есои аб=40, ао=85.

Ответы

Автор ответа: Kekit
0
Радиус опущенный в точку касания перпендикулярен самой касательной, таким образом треугольник AOB прямоугольный с гипотенузой AO, по теореме Пифагора мы найдем BO, т.к BO=R. BO=√(85^2-40^2)=75. Ответ: 75.
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