Question

решите уравнение: 2х+3$sqrt{3} sin( frac{3P}{2} ) - 5 = 0$

Answer 1

Решение
2х+3√3sin(3π/2) - 5 = 0
2х+3√3sin(π + π/2 ) - 5 = 0
2х - 3√3sin(π/2 ) - 5 = 0
2х - 3√3 * 1 - 5 = 0
2x - 3√3 - 5 =  0
2x = 3√3 + 5
x = ( 3√3 + 5)/2