Question

log₂(x+3) - log₂(x-1) = 2 - log₂(2x-8)

Answer 1

Log(x+3)/(x-1)=Log4/(2x-8) 4*(x-1)=(2x-8)*(x+3) 4x-4=2x^2+6x-8x-24 2x^2-6x-20=0 Регаем уравнение и получаем x1= 5 x2=-2