Question

Найти производную у=16/х^2 (х-4)

Answer 1

$y=frac{16}{x^2(x-4)}; ; ; to ; ; ; y=frac{16}{x^3-4x^2}qquad (; ; (frac{C}{u})'=-frac{Ccdot u'}{u^2})\\y'=-frac{16cdot (3x^2-8x)}{x^4(x-4)^2}=-frac{16cdot (3x-8)}{x^3(x-4)^2}$