Предмет: Химия, автор: Qurron

Li2CO3: HCl, NaOH, ZnCl2, KNO3, HNO3, Ba(OH)2, MnBr2

С какими из веществ реагирует Li2CO3, напишите в виде молекулярных уравнений. Подробно и красиво.

Ответы

Автор ответа: vivalaviva12
0

Li2CO3 + 2HCl =2LiCl + H2O + CO2

Li2CO3 + 2NaOH = не реагирует, т.к. не образуется осадок

Li2CO3 + ZnCl2 = не реагирует

Li2CO3 + HNO3 = не реагирует

Li2CO3 + Ba(OH)2 = 2LiOH + BaCO3 (осадок)

Li2CO3 + MnBr2 = 2LiBr + MnCO3 (осадок)

 

Похожие вопросы
Предмет: Русский язык, автор: iorunbasarova98
Предмет: Английский язык, автор: karpovayekater
ПОМОГИТЕ ПОЖАЛУЙСТА! НУЖНО СОСТАВИТЬ 10 ВОПРОСОВ НА АНГЛ. ЯЗЫКЕ К ЭТОМУ ТЕКСТУ:

My Master degree study
This year I entered the magistracy course to increase my knowledge in economics. I passed two entrance examinations – in English and the special subject. So now I am a first year master student of Mykolaiv National University named after V.O. Sukhomlinskiy. I'm attached to the Statistics Department. In the course of my post-graduate studies I am to defend my Master degree paper and pass State Examinations in special subject. After that I am planning to pass candidate examinations in philosophy, English and the special subject.
My research deals with economics. The theme of my Master degree paper (graduate work) is "Computer-Aided Tools for…". I was interested in the problem when a student so by now I have collected some valuable data for my thesis.
I work in close contact with my research adviser (supervisor). He graduated from Kiiv State University 15 years ago and got his doctoral degree at the age of 40. He is the youngest Doctor of Sciences at our University. He has published a great number of research papers in journals not only in this country but also abroad. He often takes part in the work of scientific conferences. When I have difficulties in my work I always consult my research adviser.
At present I am engaged in collecting the necessary data. I hope it will be a success and I will be through with my work on time.
Предмет: Информатика, автор: Ника100