Question

Найдите корни и промежуток

$3x^2-10x+3 textgreater 0$

Answer 1

$1) 3 x^{2} -10x+3=0 \ D=10^2-4*3*3=100-36=64=8^2 \ \ x_1= frac{10+8}.{2*3} frac{18}{6} =3 \ \ x_2=frac{10-8}{2*3}= frac{1}{3} \ \ \ 2) 3 x^{2} -10x+3 textgreater 0 \ \ +++( frac{1}{3} )---(3)+++ textgreater x \ \ xin (-infty;frac{1}{3}) U (3;+infty)$