Question

Помогите решить неравенство.
(x-5)^2<√7(x-5)

Answer 1

Решение
(x-5)^2<√7(x-5)
(x-5)^2 - √7(x-5) < 0
(x - 5)*(x - 5 - √7) < 0
1) x - 5 = 0
x₁ = 5
2)  x - 5 - √7) = 0
x₂ = 5 + √7
x ∈ (5; 5 + √7)