Question

Помогите плиз хотябы 1 или 2

Answer 1

1) a) x^1/2*x^1/4*x^-6/8=
x^4/8*x^2/8*x^-6/8=x^6/8*x^-6/8=x
b) (x^1/6)^3/x^1/2=x^3/6/x^1/2=x

2) a) (2^2)^-1/2*(2^3)^4/5/2^2/5=2^-1*2^12/5/2^2/5=2^7/5/2^2/5=2^5/5=2
b) ((10^-3)^1/3*10^3)^-1/2=(10^-1*10^3)^-1/2=(10^2)^-1/2=10^-1=0,1

Больше, увы, не могу