Question

(x-8)^2=(x-12)^2 помогите с уравнением

Answer 1

$(x-8)^2=(x-12)^2\\(x-8)^2-(x-12)^2=0\\A^2-B^2=(A-B)cdot (A+B)\\(x-8-(x-12))cdot (x-8+x-12)=0\\4cdot (2x-20)=0\\2x-20=0\\x=10$