Question

(4x-12)(3+4x+x^2)/(x^2+2x+1)(9-x^2) Прошу,срочно!

Answer 1

(4x-12)(3+4x+x^2)/(x^2+2x+1)(9-x^2) 
1)3+4x+x^2 = 0 
D = 16 - 12 = 4
x1 = -3, x2 = -1
(x+3)(x+1)
4(x-3)(x+3)(x+1)/(x+1)^2 *(- (x-3)(x+3))= -(4/x+1)