Question

Решите систему уравнений:
cos((pi/2) + x) + sin((3pi/2) - y) = 1
x+y= -(3pi/2)

Answer 1

{-sinx-cosy=1
{x+y=-3π/2⇒x=-3π/2-y
-sin(-3π/2-y)-cosy=1
sin(3π/2+y)-cosy=1
-cosy-cosy=1
cosy=-1/2
y=-2π/3 ⇒x=-3π/2+2π/3=-5π/6
y=2π/3⇒x=-3π/2-2π/3=-13π/6