Question

решите плизз 95 96 номер

Answer 1

$1) ( b^{3}p n^{2} ) ^{2} = b^{6}p^{2}n^{4} \ 2) a^{3} p^{9} q^{12} \ 3) a^{6}b^{6}c^{9} \ 4)a^{14}b^{2}c^{6}$

$1) frac{1}{2}* 2^{2}* 1^{4}* frac{1}{2}* frac{3}{4}= frac{1*2*1*3}{1*2*4}= frac{6}{8}= frac{3}{4} \ 2)-4* 1^{2}* frac{1}{4} ^{2}* 2^{2}*6*1^{4}*2^{3}= frac{-4*1*4*6*2}{2}= frac{-192}{2}=-96$