Question

∫2П(6-7х^2)dx полное решение

Answer 1

$intlimits {2pi(6-7x^2)} , dx = 2piintlimits {(6-7x^2)} , dx = 2pi*[intlimits {6} , dx - intlimits {7x^2} , dx ]=$

$=2pi*[6*intlimits {} , dx - 7*intlimits {x^2} , dx ]= 2pi*[6*x - 7* frac{x^{2+1}}{2+1} ]+C=$

$=2pi(6x-frac{7}{3}x^3)+C$