Question

sin(2п-х)-cos(3п/2-х) решите

Answer 1

sin(2п-x) = sin(-x) = -sin(x),
cos( (3п/2) - x) = cos(3п/2)*cos(x) + sin(3п/2)*sin(x) = 0*cos(x) + (-1)*sin(x) =
= -sin(x),
Исходное выражение = -sin(x) - ( -sin(x) ) = - sin(x) + sin(x) = 0.