Question

решите систему уравнений {х^2+у=14 {х-2у=-1

Answer 1

$left { {{y=14-x^2} atop {x-28+2x^2+1=0}} right. \ left { {{y=14-x^2} atop {2x^2+x-27=0}} right. \ left { {{y=14-x^2} atop {x_{1} =- frac{3}{2} };x x_{2}=2 } right. \ left { {{y_{1} = frac{47}{4};y_{2}=4 } atop { x_{1} =- frac{3}{2} };x_{2}=2} right.$