Question

Каковы корни?$frac{(x+1) (x-4) ^{2} }{x+2} leq 0$

Answer 1

$frac{(x+1)( x^{2} -8x+16)}{x+2} = frac{x^{3}-8 x^{2} +16x+ x^{2} -8x+16 }{x+2} = frac{ x^{3}-7 x^{2} -8x+16}{x+2}$