Question

y=sin 2x + log6 x найти производную функцию

Answer 1

 

$<var>y = sin2x + log_6x\\\\y' = (sin2x + log_6x)' = <var>(sin2x)' + (log_6x)' </var>=\\\\ <var><var>2cos2x + (\frac{lnx}{ln6})</var></var>' = <var><var><var>2cos2x +<var><var><var><var>\frac{1}{ln6}</var></var></var></var> (lnx)</var></var>' </var>=2cos2x + \frac{1}{xln6}</var>$