Question

cosx\3=1\2 (Решить уравнение).................

Answer 1

$<var>cos\frac{x}{3}=\frac{1}{2} \\ \\ \frac{x}{3}=б\frac{\pi}{3}+2\pi n \\ \\ x=б\pi+6\pi n,\ \ \ \ \ n \in Z</var>$

Answer 2

cosx\3=1\2

х/3 = +/- arccos1/2 + 2πn

x/3 = +/- π/3 + 2πn |*3

x = +/- π + 6πn

x = π + 6πn

x = - π + 6πn, n ∈ Z