Question

Решите пожалуйста. 7 класс

Answer 1

№2.

$<var>\frac{3}{8}\cdot x=\frac{5}{7}</var>$

$<var>\frac{3x}{8}=\frac{5}{7}</var>$

$<var>3x*7=8*5</var>$

$<var>21x=40</var>$

$<var>x=\frac{40}{21}\approx1,9</var>$

 

№3.

$<var>(\frac{3}{4}+(\frac{1}{2})^2+\frac{1}{3}):1\frac{1}{6}=1\frac{3}{21} \\ \frac{3}{4}+(\frac{1}{2})^2+\frac{1}{3}=\frac{^{3/}3}{4}+\frac{^{3/}1}{4}+\frac{^{4/}1}{3}=\frac{3*3+3*1+4*1}{12}=\frac{16}{12}=\frac{4}{3} \\ \frac{4}{3}:1\frac{1}{6}=\frac{4}{3}:\frac{7}{6}=\frac{4}{3}\cdot \frac{6}{7}=\frac{4\cdot 6}{3\cdot 7}=\frac{24}{21}=1\frac{3}{21}</var>$