Question

Упрастите выражение sin 2п/3 cos п/6+cos 2п/3 sin п/6

Answer 1

sinacosb+cosasinb=sin(a+b)
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sin2π/3cosπ/6+cos2π/3sinπ/6=sin(2π/3+π/6)=sin5π/6=sin(π-π/6)=sinπ/6=1/2