Question

Помогите решить задание 6.23

Answer 1

u^1/2=√u
----------------------------
1)(u-1)/(u+√u+1);(√u+1)/(√u³-1)=
=(√u-1)(√u+1)/(u+√u+1) * (√u-1)(u+√u+1)/(√u+1)=(√u-1)²
2)2:1/√u=2√u
3)(√u-1)+2√u=u-2√u+1+2√u=u+1