Question

Cu(OH)2-годроксид меди
w-?

Answer 1

M(Cu(OH)2)=63.5+(16+1)*2=97.5 g/mol
W(Cu)63.5/97.5*100%=65.13%
W(O)=16*2/97.5*100%=32.82%
W(H)=1*2/97.5*100%=2.05%