Предмет: Алгебра, автор: Scholl533

разложите на множители:
x2+10x-11
2) 3y^2-4y+1

Ответы

Автор ответа: zhenyaM2002
0
x²+10x-11 = x²+11x -x -11 = x(x+11) - 1(x+11) =(x+11)(x-1)

3y²-4y+1 = 3y²-3y-y+1 = 3y(y-1) -1(y-1) = (y-1)(3y-1)
Автор ответа: Timoxa987
0
1)D=100-4•(-11)=144
X1=(10+12)/2=11
X2=(10-12)/2=-1
(x-11)(x+11)
2) D=16-4•3=4
Y1=(4+2)/6=1
Y2=(4-2)/6=1/3
(y-1)(y-1/3)
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