Question

Помогите буду благодарен

Answer 1

1) b) (a+4)/a -(a+6)/(a-2) =
=((a+4)(a-2) -a(a+6)) /a(a-2) =
=(a²+2a-8 -a²-6a) /a(a-2) =
=(-6a-8) /a(a-2)

v) =((a+1)(a+1) -(a-1)(a-1)) /2a(a-1)(a+1) =
=(a²+2a+1 -a²+2a-1) /2a(a-1)(a+1)=
=4a /2a(a² -1) =2 /(a² -1)

g) =(x+2) /2(x-2) -(3x-2) /x(x-2) =
=(x(x+2) -2(3x-2)) /2x(x-2) =
=(x²+2x -6x+4) /2x(x-2) =
=(x² -4x +4) /2x(x-2) =(x-2)² /2x(x-2) =
=(x-2) /2x


2) =(5-3x +2x) /(25-x²) =(5-x) /(5-x)(5+x) =
=1 /(5+x) =1 /(5 -1.5) =1 /3.5 =1 : 35/10 =10/35 =2/7