Question

помогите решить!цена 25 баллов!

Answer 1

$displaystyle 1).. sqrt[3]{2ab}* sqrt[3]{4a^{2}b }* sqrt[3]{27b}=3 sqrt[3]{8a^{3}b^{3}}=6ab; \ \ 2)..sqrt[4]{abc}* sqrt[4]{a^{3}b^{2}c}* sqrt[4]{b^{5}c^{2}}= sqrt[4]{a^{4}b^{8}c^{4}}=ab^{2}c; \ \ 3).. sqrt[3]{ sqrt[3]{a^{18} } }+(sqrt{ sqrt[3]{a^{4} } })^{3}= sqrt[3]{a^{6}}+ (sqrt[6]{a^{4} })^{3}=a^{ frac{6}{3} }+a^{ frac{12}{6}}=a^{2}+a^{2}=2a^{2};$
$displaystyle 4)..(sqrt{sqrt[3]{x^{2}}})^{3}+2(sqrt[4]{sqrt{x}})^{8}= x^{frac{6}{6}}+2x^{frac{8}{8}}=x+2x=3x;\\5)..sqrt[3]{sqrt{x^{6}y^{12} }}-( sqrt[5]{xy^{2}})^{5}=x^{frac{6}{6}}y^{frac{12}{6}}-(xy^{2})^{frac{5}{5}}=xy^{2}-xy^{2}=0;\\6)..((sqrt[5]{asqrt[5]{a}})^{5}-sqrt[5]{a}):sqrt[10]{a^{2}}=((a sqrt[5]{a})^{frac{5}{5}}-sqrt[5]{a}):a^{frac{2}{10}}=\\=(asqrt[5]{a}-sqrt[5]{a})*a^{frac{10}{2}}=a^{frac{1}{5}}(a-1)*a^{5}=a^{frac{5}{5}}(a-1)=a-1;$