Question

НАЙДИТЕ РАЦИОНАЛЬНЫЕ КОРНИ УРАВНЕНИЯ
X^4-2x^3-8x^2+13x-24=0

Answer 1

x⁴-2x³-8x²+13x-24=0
x₁=-3
x⁴-2x³-8x²+13x-24  |_x+3_
x⁴+3x³                        | x³-5x²+7x-8
--------
          -5x³-8x²
          -5x³-15x²
         ---------
                    7x²+13x
                    7x²+21x
               ------------
                                -8x-24
                                 -8x-24
                                 ---------
                                            0
x³-5x²+7x-8=0
x₂=3,69