Question

Вычислить предел: lim(х->-2) х^3+3х^2+2х/х^2-х-6

Answer 1

$<var>\lim_{x \to -2} \frac{x^3+3x^2+2x}{x^2-x-6}=\lim_{x \to -2} \frac{x(x+2)(x+1)}{(x+2)(x-3)}=\\ =\lim_{x \to -2} \frac{x(x+1)}{(x-3)}=\frac{-2 * (-1)}{-5}=-0.4\\</var>$