Question

Представьте в виде дроби:

3x-1/x^2+x-9/3x

1/2a-b-1/2a+b

5/c+3-5c-2/c^2+3c

Answer 1

$frac{3x-1}{x^2} +frac{x-9}{3x} = frac{9x-3+x^2-9x}{3x^2} = frac{x^2-3}{3x^2} \ frac{1}{2a-b}- frac{1}{2a+b} = frac{2a+b-2a+b}{4a^2-b^2}= frac{x^2-3}{3x^2} \ frac{5}{c+3} - frac{5c-2}{c^2+3c} = frac{5c-5c-2}{c^2+3c} =- frac{2}{c^2+3c}$