Question

Под буквой б помогите

Answer 1

$frac{y+1}{y+2} + frac{y+2}{y+1} = frac{25}{12} \ x^2-2xy+y^2=0 \ \ frac{(y+1)^2+(y+2)^2}{(y+2)(y+1)} = frac{25}{12} \ (x-y)^2=0 \ \ frac{y^2+2y+1+y^2+4y+4}{y^2+3y+2} = frac{25}{12} \ x=y \ \ 25(y^2+3y+2)=12(2y^2+6y+5) \ y^2+3y-10=0 \ D=49 \ y_{1} =-5 \ x_{1} =-5 \ y_{2} =2 \ x_{2} =2$