Question

Помогите пж
1)х^2-2x+2=0
2)х^2+36=0

Answer 1

1) x^2-2-2x+2=0
x^2-2x=0
x•(x-2) =0
x=0. x=0
x-2=0. x=2

2) x^2+36=0
x^2=-36
x=+√-36
x є R