Question

tg*cos²/sin-sin³
Упростить

Answer 1

$frac{tgx*cos^2x}{sinx-sin^3x} = frac{tgx*cos^2x}{sinx(1-sin^2x)} = frac{tg*cos^2x}{sinx*cos^2x} = frac{tgx}{sinx} = frac{sinx}{cosx}: frac{sinx}{1}= frac{sinx}{cosx*sinx}$$= frac{1}{cosx}$